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Question

Find the area of parallelogram with adjacent sides formed by P and Q, where P=2^i+3^j+4^k and Q=3^i+2^j2^k expressed in metre.

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Solution

Given side P=2^i+3^j+4^kand^Q=3^i+2^j2^k
Now we know area of parallelogram =P×Q
P×Q=^i^j^k234322
=^i(68)^j(412)+^k(49)
=14^i+16^j5^k
Now magnitude of P×Q==122+162+(5)2=144+256+25=425=20.16m2

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