Find the area of parallelogram with adjacent sides formed by →P and →Q, where →P=2^i+3^j+4^k and →Q=3^i+2^j−2^k expressed in metre.
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Solution
Given side →P=2^i+3^j+4^kand^Q=3^i+2^j−2^k Now we know area of parallelogram =→P×→Q →P×→Q=^i^j^k23432−2 =^i(−6−8)−^j(−4−12)+^k(4−9) =−14^i+16^j−5^k Now magnitude of →P×→Q==√−122+162+(−5)2=√144+256+25=√425=20.16m2