Question

Find the area of pentagon $ABCDE$ shown in figure, if $AD=11cm,AG=6cm,AF=2cm,AB=3cm,CG=6cm,EF=4cm$

Answer 1

$AD=11cm$

$AG=6cm$

$AF=2cm$

$AB=3cm$

$CG=6cm$

$EF=4cm$

Let us assume

$FG=4cm$

& $GD=5cm$

Now

Area of fig $I=\frac{1}{2}\times$ (sum of parallelogram sides) $\times Lt$

$=\frac{1}{2}\times (3+6)\times 6$

$=\frac{1}{2}\times 9\times 6=27c{m}^2$

Area of fig $II=\frac{1}{2}\times base\times salt$

$=\frac{1}{2}\times 5\times 6=15c{m}^2$

Area if $III=\frac{1}{2}\times 9\times 4=18c{m}^2$

area of fig $IV=\frac{1}{2}\times 2\times 4=4c{m}^2$

Total area of pentagonal $ABCDE=$ Area of (fig $I+figII+figIII+figIV$)

$=(27+15+18+4)c{m}^2$

$=(42+22)c{m}^2$

$=54c{m}^2$