Question

Find the area of polygon $PQRSTU$ shown in adjoining figure, if $PS=11cm,PY=9cm,PX=8cm,PW=5cm,PV=3cm,$$QV=5cm,UW=4cm,$$RX=6cm,$ $TY=2cm$

Answer 1

$PS=11cm$

$PY=9cm$

$PX=8cm$

$PW=5cm$

$PV=3$

$\left(1\right)△PQV=\frac{1}{2}\times 5\times 3=7.5$

$\left(2\right)△PWV=\frac{1}{2}\times 5\times 4=10$

$\left(3\right)△RYS=\frac{1}{2}\times 3\times 6=9$

$\left(4\right)△SYT=\frac{1}{2}\times 2\times 2=2$

$\left(5\right)\frac{1}{2}\times 1\times 5=2.5$

$\left(6\right)\frac{1}{2}\times 2\times (5-9)=4$

$10+10+9+6$

$=20+15$

$=35$