Question

Find the area of quadrilateral $ABCD$

Answer 1

Area of quadrilateral $ABCD=\frac{1}{2}d(h_1+h_2)$
Sum of the length of perpendicular from the remaining two vertices on the diagonal $AC=(h_1+h_2)$
$h_1+h_2=12cm$.
Length of the diagonal $\left(BD\right)=11cm$.
$\therefore$ Area of quadrilateral $=\frac{1}{2}d(h_1+h_2)=\frac{1}{2}\times 12\times 11=6\times 11=66c{m}^2$.