Question

Find the area of quadrilateral ABCD whose vertices are A(-4,-2), B(-3,-5), C(3,-2) and D(2,3).

Answer 1

Area of ABCD=$\frac{1}{2}\left|\begin{array}{cc}-4& -2\\ -3& -5\\ 3& -2\\ 2& 3\\ -4& -2\end{array}\right|=\frac{1}{2}\left|48\right|=24sq.units$