Find the area of quadrilateral formed by joining the points (-4, 2), (1,-1)(4, 1) and (2,5):
24.5
Let A, B, C, D be the points (-4, 2), (1, -1), (4, 1) and (2, 5) respectively.
Then the area of the quadrilateral ABCD =12(−4×−1−2×1+1×1−4×−1+4×5−2×1+2×2×−5×−4)
=12(4−2+1+4+20+4+20)
=492=24.5 squre units.
NOTE: Area of quadrilateral =12(x1y2−x2y1)+(x2y3−x2y3)+(x3y4−x4y3)+(x4y1−x1y4))