Find the area of quadrilateral one of whose diagonals is $30$ cm long and the perpendiculars from the other two vertices are $19$ cm and $11$ cm respectively.

420

sq. cm

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440

sq. cm

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450

sq. cm

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480

sq. cm

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Solution

The correct option is C $450$ sq. cm
$B C = 30 c m$
Area of quadrilateral $=$ Area of triangle ABC $+$ Area of triangle $B C D$
$\Rightarrow \frac{1}{2} \times 30 \times 11 + \frac{1}{2} \times 30 \times 19$
$\Rightarrow 15 (11 + 19)$
$= 450 c m^{2}$

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Find the area of quadrilateral one of whose diagonals is 30 cm long and the perpendiculars from the other two vertices are 19 cm and 11 cm respectively.

The correct option is C 450 sq. cmBC=30cmArea of quadrilateral = Area of triangle ABC+ Area of triangle BCD⇒12×30×11+12×30×19⇒15(11+19)=450cm2

Find the area of quadrilateral one of whose diagonals is $30$ cm long and the perpendiculars from the other two vertices are $19$ cm and $11$ cm respectively.

The correct option is C $450$ sq. cm
$B C = 30 c m$
Area of quadrilateral $=$ Area of triangle ABC $+$ Area of triangle $B C D$
$\Rightarrow \frac{1}{2} \times 30 \times 11 + \frac{1}{2} \times 30 \times 19$
$\Rightarrow 15 (11 + 19)$
$= 450 c m^{2}$