Find the area of quadrilateral whose diagonal length is $10$ cm, height $h_{1} = 5$ cm and height $h_{2}$ is $7$ cm.

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Solution

BC= $10$ cm
$h_{1} = 5 c m, h_{2} = 7 c m$
Area of Quadrilateral=area $(\triangle ABC)+area $(△ B C D)$
= $\frac{1}{2} \times B C \times h_{1} + \frac{1}{2} \times B C \times h_{2} = (\frac{1}{2} \times 10 \times 5 + \frac{1}{2} \times 10 \times 7) {c m}^{2} = (25 + 35) {c m}^{2} = 60 {c m}^{2}$

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Find the area of quadrilateral whose diagonal length is 10cm, height h1=5cm and height h2 is 7cm.

BC=10cmh1=5cm,h2=7cmArea of Quadrilateral=area $(\triangle ABC)+area (△BCD)=12×BC×h1+12×BC×h2=(12×10×5+12×10×7)cm2=(25+35)cm2=60cm2

Find the area of quadrilateral whose diagonal length is $10$ cm, height $h_{1} = 5$ cm and height $h_{2}$ is $7$ cm.

BC= $10$ cm
$h_{1} = 5 c m, h_{2} = 7 c m$
Area of Quadrilateral=area $(\triangle ABC)+area $(△ B C D)$
= $\frac{1}{2} \times B C \times h_{1} + \frac{1}{2} \times B C \times h_{2} = (\frac{1}{2} \times 10 \times 5 + \frac{1}{2} \times 10 \times 7) {c m}^{2} = (25 + 35) {c m}^{2} = 60 {c m}^{2}$