Find the area of Rectangle whose perimeter is $40 m$ and length and breadth ratio is $3 : 1$

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Solution

The ratio of length and breadth is $3 : 1$
The common factor be $x$
The length is $3 x$
The breadth is $x$
The perimeter is $2 (l + b) = 40 3 x + x = \frac{40}{2} 4 x = 20 x = 5$
The length is $15 c m$
The bradth is $5 c m$
The area is $15 (5) = 75 c m^{2}$

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Ratio of area is to perimeter of a rectangle whose length and breadth are 18 and 12 respectively is

Find the length and perimeter of a rectangle, whose: area $= 120 c m^{2}$ and breadth =8 cm

(i)

= 25 c m

= 18 c m

(i i)

= 27 c m

= 17 c m

(i i i)

= 7.2 c m

= 80 c m

40 m

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