Find the area of rectangle with length $x - 3$ and breadth $x + 3$ .

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Solution

Area of rectangle = $l e n g t h \times b r e a d t h$ = $(x - 3) (x + 3) = x^{2} - 9$ sq. units

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Question 93 (ii)

The following expression is the area of a rectangle. Find the possible length and breadth of the rectangle.

$x^{2} - 3 x + 2$

The area of a rectangle gets reduced by 9 square units. if its length is reduced by 5 units and breadth is increased by 3 units. However, if the length of this rectangle increases by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

Let the length of the rectangle = x units and its breadth = y units

According to first condition :
$(x - 5) (y + 3) = x y - 9$ and

According to second condition:
$(x + 3) (y + 2) = x y + 67$

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Q. Area of a rectangle with length 3 cm and breadth 2 cm =

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Find the area of rectangle with length x−3 and breadth x+3.

Area of rectangle = length×breadth = (x−3)(x+3)=x2−9 sq. units

Find the area of rectangle with length $x - 3$ and breadth $x + 3$ .

Area of rectangle = $l e n g t h \times b r e a d t h$ = $(x - 3) (x + 3) = x^{2} - 9$ sq. units