Question

Find the area of rectangular park which is $18\frac{3}{5}$m long and $8\frac{2}{3}$m breadth.

Answer 1

The length of park is

$l=18\frac{3}{5}m$

The breadth of park is

$b=8\frac{2}{3}m$

We can write mixed fraction

as below:

$a\frac{b}{c}=a+\frac{b}{c}=\frac{ac+b}{c}$

Area of park $=A=l\times b$

$A=\left(18\frac{3}{5}\right)\times \left(8\frac{2}{3}\right)$

$=(18+\frac{3}{5})\times (8+\frac{2}{3})$

$=18\times 8+18\times \frac{2}{3}+\frac{3}{5}\times 8+\frac{3}{5}\times \frac{2}{3}$

$=144+12+\frac{24}{5}+\frac{2}{5}$

$A=156+\frac{26}{5}=156+5+\frac{1}{5}=161\frac{1}{5}$

$A=161\frac{1}{5}$