Let side of the rhombus be 's' and diagonals be d and d'
Given , perimeter of rhombus=200m
➡4s= 200
➡s=50 m
Also given , d'=80m
We know , diagonals of a rhombus are perpendicular bisectors.
➡(d/2)²+(d'/2)²=s²
➡(d/2)²=900
➡d=2*30=60 m
Area of the rhombus = d*d'/2 = 60*80/2 = 2400 m²