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Question

Find the area of rhombus whose perimeter is 200m and one of the diagonal is 80m

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Solution

Let side of the rhombus be 's' and diagonals be d and d'
Given , perimeter of rhombus=200m
➡4s= 200
➡s=50 m
Also given , d'=80m
We know , diagonals of a rhombus are perpendicular bisectors.
➡(d/2)²+(d'/2)²=s²
➡(d/2)²=900
➡d=2*30=60 m
Area of the rhombus = d*d'/2 = 60*80/2 = 2400 m²

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