Find the area of right angled triangle whose hypotenuse is 15 cm and one of the sides is 12 cm.

45 c m^{2}

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54 c m^{2}

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35 c m^{2}

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27 c m^{2}

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Solution

The correct option is B $54 c m^{2}$
First we need to find the other side of the triangle:

We know that $A B^{2} = A C^{2} - B C^{2}$

= $15^{2} - 12^{2}$

= 225 - 144

= 81

Therefore, AB = 9

Therefore, area of the triangle

= $\frac{1}{2} \times b a s e \times h e i g h t$

= $\frac{1}{2} \times 12 \times 9$

= $54 c m^{2}$

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Find the area of right angled triangle whose hypotenuse is 15 cm and one of the sides is 12 cm.

The correct option is B 54 cm2First we need to find the other side of the triangle: We know that AB2=AC2−BC2 = 152−122 = 225 - 144 = 81 Therefore, AB = 9 Therefore, area of the triangle = 12×base×height = 12×12×9 = 54 cm2