Find the area of right angled triangle whose hypotenuse is 15 cm and one of the sides is 12 cm.

44 cm²

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54 cm²

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64 cm²

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74 cm²

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Solution

The correct option is B
54 cm²

AB $^{2}$ = AC $^{2}$ - BC $^{2}$
= 15 $^{2}$ - 12 $^{2}$
= 225 - 144
= 81
AB = 9
Therefore, area of the triangle = $\frac{1}{2}$ $\times$ base $\times$ height
= $\frac{1}{2}$ $\times$ 12 $\times$ 9
= 54 cm $^{2}$

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Find the area of right angled triangle whose hypotenuse is 15 cm and one of the sides is 12 cm.

The correct option is B 54 cm2 AB2= AC2- BC2 = 152- 122 = 225 - 144 = 81 AB = 9 Therefore, area of the triangle = 12 × base × height = 12 × 12 × 9 = 54 cm2

The correct option is B
54 cm²

AB $^{2}$ = AC $^{2}$ - BC $^{2}$
= 15 $^{2}$ - 12 $^{2}$
= 225 - 144
= 81
AB = 9
Therefore, area of the triangle = $\frac{1}{2}$ $\times$ base $\times$ height
= $\frac{1}{2}$ $\times$ 12 $\times$ 9
= 54 cm $^{2}$