Question

find the area of right angled triangle with hypotenuse 40 Cm and one of its side be 24cm.

Answer 1

Answer :

Given : In right angled triangle with hypotenuse = 40 cm

And

One of its side be 24 cm

We know from Pythagoras theorem :

Hypotenuse ² = Opposite ² + Adjacent ² , So

40² = 24² + Adjacent ² ,

1600 = 576 + Adjacent ² ,

Adjacent ² = 1024

Adjacent ² = 32²

Adjacent = 32

So,

Other side of right angle triangle = 32 cm

We know in right angle triangle sides other than hypotenuse are perpendiculars to each other .

So , we can say one of it's side base of triangle = 24 cm

And

Height of triangle = 32 cm

And we know formula for area of triangle :

Area of triangle = $\frac{1}{2}\times \mathrm{Base}\times \mathrm{Height}$

So,

Area of our given right angle triangle = $\frac{1}{2}\times 24\times 32=12\times 32=\mathbf{384}\mathbf{}{\mathbf{cm}}^{\mathbf{2}}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{(}\mathbf{}\mathbf{Ans}\mathbf{}\mathbf{)}$