Question

Find the area of sector which subtends an angle of ${45}^o$ at the centre of circle whose radius is 14 cm.

• A. 22 $c{m}^2$
• B. 42 $c{m}^2$
• C. 77 $c{m}^2$
• D. 154 $c{m}^2$

Answer 1

The correct option is C 77 $c{m}^2$

Area of sector = $\frac{angle}{{360}^o}$$\times$$\pi$$r^2$
= $\frac{{45}^o}{{360}^o}$$\times$$\frac{22}{7}$$\times$${14}^2$
= $\frac{1}{8}$$\times$$\frac{22}{7}$$\times$196
= 11$\times$7 = 77 $c{m}^2$