Find the area of the 1.5 m wide pathway (green) if length is twice the breadth. Breadth is equal to 6 m..

Open in App

Solution

Breadth of the rectangle = EH = FG = 6 m

Length of rectangle = AB = CD = 12 m

Area of the pathway ABCD $= 12 m \times 1.5 m = 18 m^{2}$

Area of the pathway EFGH $= 6 m \times 1.5 m = 9 m^{2}$

Area (PQRS) $= 1.5 m \times 1.5 m = 2.25 m^{2}$ (This area is taken twice)

Total area of pathway = Area (ABCD) + Area (EFGH) - Area (PQRS)

$= (18 + 9 - 2.25) m^{2} = 24.75 m^{2}$

Suggest Corrections

Similar questions

Find the area of the 1.5 m wide pathway (green) if length is twice the breadth. Breadth is equal to 6 m..

Find the area of the 1.5 m wide pathways (green) if length is twice of breadth which is equal to 6 m (in square cm).

Find the area of the 1.5 m wide pathways (green) if length of the outer rectangle is twice its breadth which is equal to 6 m (in $c m^{2}$ ).

Find the area of the pathway of uniform width 1.5 m given that the length of a rectangular field is twice its breadth and the breadth measures 6 m.

Join BYJU'S Learning Program