Question

Find the area of the 1.5 m wide pathway (green) if length is twice the breadth. Breadth is equal to 6 m..

Answer 1

Breadth of the rectangle = EH = FG = 6 m

Length of rectangle = AB = CD = 12 m

Area of the pathway ABCD $=12m\times 1.5m=18m^2$

Area of the pathway EFGH $=6m\times 1.5m=9m^2$ ​

Area (PQRS) $=1.5m\times 1.5m=2.25m^2$ (This area is taken twice)

Total area of pathway = Area (ABCD) + Area (EFGH) - Area (PQRS)

$=(18+9-2.25)m^2=24.75m^2$