Find the area of the 1.5 m wide pathways (green) if the length is twice of breadth which is equal to 6 m (in square cm).
24.75
Breadth of the rectangle = EH = FG = 6 m
Length of rectangle = AB = CD = 12 m
Area of the pathway ABCD = 12 m × 1.5 m = 18 m2
Area of the pathway EFGH = 6 m × 1.5 m = 9 m2
Area (PQRS) = 1.5 m × 1.5 m = 2.25 m2 (This area is taken twice)
Total area of pathway = Area (ABCD) + Area (EFGH) – Area (PQRS)
= (18 + 9 – 2.25) m2 = 24.75 m2