Find the area of the above shown figure( in m²). Where ABE is is equilateral triangle, ABCD is a rectangle, arc BC and arc AD are semi circle.

351.7

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400

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451.7

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252.45

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Solution

The correct option is A
351.7

Area of the rectangular part = length x breadth

= 20 x 7 = 140 sq m

Area of Semi-circular portions: = π x $\frac{r^{2}}{2}$ + π x $\frac{r^{2}}{2}$ = π x $r^{2}$ = π x 3.5 × 3.5 = 38.5m²

Area of equilateral triangular part = $\frac{\sqrt{3} (s i d e)^{2}}{4}$ = $\frac{\sqrt{3} (20)^{2}}{4}$ = 173.20 m²

Total area = 140 + 38.5 + 173.20 = 351.70 m²

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Find the area of the above shown figure( in m2). Where ABE is is equilateral triangle, ABCD is a rectangle, arc BC and arc AD are semi circle.

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