Find the area of the canvas required to make a conical tent 14m high and 96m in diameter. Given that:
1) canvas used in folds and stitchings is 20% of the curved surface area of the tent.
Find the area of the canvas required to make a conical tent 14m high and 96m in diameter. Given that:
1) canvas used in folds and stitchings is 20% of the curved surface area of the tent.
Radius of that conical tent is =96/2=48m
Slant height of the cone (l) = √(r² + h² ) = √(48² + 14² )m = √(2304 + 196) = √2500 m = 50 m.
Curved surface area of the conical part = πrl = πx48x50 m²
Hence the quantity of canvas or the area of the canvas required to make the tent = 120% of the surface area of the tent (because here it is said that for folding and stitching need extra 20% of that tent curved surface area, so if the curved surface area is 100% then the total area of that canvas will be 100%+20%=120%)
= ( 120/ 100)×πx48x50 = 9051.42 m² approximately.
Radius of that conical tent is =96/2=48m
Slant height of the cone (l) = √(r² + h² ) = √(48² + 14² )m = √(2304 + 196) = √2500 m = 50 m.
Curved surface area of the conical part = πrl = πx48x50 m²
Hence the quantity of canvas or the area of the canvas required to make the tent = 120% of the surface area of the tent (because here it is said that for folding and stitching need extra 20% of that tent curved surface area, so if the curved surface area is 100% then the total area of that canvas will be 100%+20%=120%)
= ( 120/ 100)×πx48x50 = 9051.42 m² approximately.
