Find the area of the circle $4 x^{2} + 4 y^{2} = 9$

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Solution

Equation of circle is $4 x^{2} + 4 y^{2} = 9 x^{2} + y^{2} = \frac{9}{4}$
So the radius of circle is $\sqrt{\frac{9}{4}} = \frac{3}{2}$
Area of circle is $π r^{2} = \frac{22}{7} \times \frac{3}{2} \times \frac{3}{2} = 7.065$

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Similar questions

4 x^{2} + 4 y^{2} = 9

x^{2} = 4 y

Find the area of the circle $4 x^{2} + 4 y^{2} = 9$ which is interior to the parabola $x^{2} = 4 y$

{4 x}^{2} + {4 y}^{2} = 9

y^{2} = 4 x

4 x^{2} + 4 y^{2} - 12 x - 12 y + 9 = 0

{(x, y) : y^{2} \leq 4 x, 4 x^{2} + 4 y^{2} = 9.

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