Question

Find the area of the closed figure bounded by the following curve
y = $x^2$, $y=0andx=3$.

Answer 1

Given curve $y=x^2$

For $y=0,x=0$

we need the area enclosed between x=0 and x=3

The area enclosed between x=0 and x=3 is ${\int }_0^3{x}^{2}dx$

$[\frac{x^3}{3}{]}_0^3=\frac{27}{3}=9$