Question

Find the area of the figure below.

• A. $13{\text{m}}^2$
• B. $15{\text{m}}^2$
• C. $16{\text{m}}^2$
• D. $13\text{m}$

Answer 1

The correct option is A $13{\text{m}}^2$

Lets name its vertices.
As we can see, the given complex figure has two rectangles namely $ABCD$ and $GHEF$.
Area of closed figure = Area of rectangle ABCD + Area of rectangle EFGH

$\to$ Area of ABCD = length $\times$ breadth
$=4\times 2=8{\text{m}}^2$
$\to$ Area of EFGH = length $\times$ breadth
$=1\times 5=5{\text{m}}^2$

Hence, Area of closed figure $=8{\text{m}}^2+5{\text{m}}^2=13{\text{m}}^2$
Option (a) is correct.