Find the area of the figure bounded by the following curves
Through the origin of coordinates draw a straight line which divides the curvilinear triangle with -vertex at the origin, bounded by the curves $y = 2 x y = 0$ and $x = 1$ , into two parts of the same size.

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Solution

$\begin{matrix} C u r v e s : y + 2 x y = 0, x = 1 S o, a r e a b o u n d e d = \frac{1}{2} \times b a s e \times h e i g h t = \frac{1}{2} \times 1 \times 2 = 1 s q u a r e u n i t . \end{matrix}$

Hence, this is the answer.

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