Find the area of the figure shown above.

20

c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

21

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

42

c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $20$ $c m^{2}$
$A B C D$ is a trapezium.
Given: $A B = 4$ cm, $C D = 6$ cm, Height $= 4$ cm
Area of trapezium $= \frac{1}{2} \times$ Sum of parallel side $\times$ height
$= \frac{1}{2} \times (6 + 4) \times 4 = 20 c m^{2}$

Suggest Corrections

Similar questions

Question 16

The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is

(a) $72 c m^{2}$ (b) $36 c m^{2}$ (c) $24 c m^{2}$ (d) $18 c m^{2}$

^{2}

^{2}

Question 17

What is the area of the rhombus ABCD below if AC = 6 cm and BE = 4 cm?

(a) $36 c m^{2}$ (b) $16 c m^{2}$ (c) $24 c m^{2}$ (d) $13 c m^{2}$

The area of figure 1 (in $c m^{2}$ ) and area of figure 2 (in $c m^{2}$ ) are ___ and ___ respectively.

The areas of figure 1 (in $c m^{2}$ ) and figure 2 (in $c m^{2}$ ) are __ and __ respectively.

Join BYJU'S Learning Program