Question

Find the area of the following combined figure.

Answer 1

Area of first rectangle $15\times 4=60c{m}^2$

Area of second rectangle $(17-4)\times 413\times 4=52c{m}^2$

Area of third rectangle $(15-4)\times 411\times 4=44c{m}^2$

Area of fourth rectangle $12\times 4=48c{m}^2$

So the area of combined figure is $60+52+44+48=204c{m}^2$