Question

Find the area of the following shape (in sq. cm)

• A. = 40 cm${}^2$
• B. = 48 cm${}^2$
• C. = 36 cm${}^2$
• D. = 24 cm${}^2$

Answer 1

The correct option is B

= 48 cm${}^2$

Area of the above shapes can be calculated in two steps

i) Area of shape marked 1

ii) Area of shape marked 2

$\Rightarrow$ Area of shape marked 1 = Area of rectangle
= length $\times$ breadth

= 4 $\times$ 9 = 36 cm${}^2$

$\Rightarrow$Area of shape marked 2 = Area of triangle
= $\frac{1}{2}\times$ base $\times$ height

= $\frac{1}{2}\times$ 6 $\times$ 4

= 12 cm${}^2$

$\Rightarrow$Area of shape = Area of shape marked 1+ Area of shape marked 2

= (36 + 12) cm${}^2$ = 48 cm${}^2$