Question

Find the area of the given figure having both the ends as semi-circles with a radius = 7 cm and lengh of the central part is 10 cm as marked.

• A. 294
• B. 150
• C. 290
• D. 248

Answer 1

The correct option is A 294

For the semicircle: radius = 7 cm.
Area of the two semi-circles = $\frac{1}{2}(\pi \times r^2)+\frac{1}{2}(\pi \times r^2)=\pi \times r^2=\frac{22}{7}\times 7\times 7=154c{m}^2$

For rectangle in middle, one side is 10 cm and the other side is equal to the diameter of the semi-circle which is = 7 + 7 = 14 cm.
Area of rectangular part = length $\times$ breadth = 10 $\times$14 = 140 $c{m}^2$

Total area = Area of the two semi-circles + Area of the rectangle = 154+140 = 294 $c{m}^2$​.