Question

Find the area of the major segment $APB$ in the given figure of a circle of radius $35cm$ and $\angle AOB={90}^o$. (use $\pi =22/7$)

Answer 1

Area of segment $=\pi r^2\times \left(\frac{obtuse\angle AOB}{360}\right)$

$=\pi r^2\times \left(\frac{270}{360}\right)=\frac{3}{4}\pi r^2=\frac{3}{4}\times \frac{22}{7}\times 35\times 35=2887.5$cm.