Find the area of the parallelogram in which- AE -4 cm and CD -8 cm-A- 16 cm 2B- 32 cm 2C- 64 cm 2D- 128 cm 2

The correct option is B 32 cm^2 Area of parallelogram = Base × Height of the parallelogram Base =8 cm Height =4 cm ⇒ Area =8× 4=32 cm^2 ...

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Standard IX

Mathematics

Area

Find the area...

Question

Find the area of the parallelogram in which, $A E = 4 c m$ and $C D = 8 c m$ .

$16 c m^{2}$

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$32 c m^{2}$

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$64 c m^{2}$

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$128 c m^{2}$

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Solution

The correct option is B
$32 c m^{2}$

Area of parallelogram $=$ Base $\times$ Height of the parallelogram

Base $= 8 c m$

Height $= 4 c m$

$\Rightarrow$ Area $= 8 \times 4 = 32 c m^{2}$

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ABCD is a parallelogram in which AE is perpendicular to CD is shown in the given figure. Also, AC = 5 cm, DE = 4 cm and area of $Δ A E D = 6 c m^{2}$ .
Find the perimeter and area of parallelogram ABCD.

Question 11

The volume of a cube is $64 c m^{3} .$ Its surface area is
(a) $16 c m^{2}$ (b) $64 c m^{2}$
(c) $96 c m^{2}$ (d) $128 c m^{2}$

Find the area of a parallelogram $A B C D$ in which $A B = 3 c m, B C = 7 c m$ and $A C = 8 c m$ .

Q. Question 12

In the given figure, EFGH is a parallelogram, altitudes FK and FI are 8 cm and 4 cm, respectively. If EF = 10 cm, then the area of EFGH is

(a)

20 c m^{2}

(b)

32 c m^{2}

(c)

40 c m^{2}

(d)

80 c m^{2}

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Find the area of the parallelogram in which, AE=4 cm and CD=8 cm.

The correct option is B 32 cm2 Area of parallelogram = Base × Height of the parallelogram Base =8 cm Height =4 cm ⇒ Area =8×4=32 cm2

Find the area of the parallelogram in which, $A E = 4 c m$ and $C D = 8 c m$ .

The correct option is B
$32 c m^{2}$

Area of parallelogram $=$ Base $\times$ Height of the parallelogram

Base $= 8 c m$

Height $= 4 c m$

$\Rightarrow$ Area $= 8 \times 4 = 32 c m^{2}$