Find the area of the parallelogram- whose diagonals are d 1-5 - and d 2-2 -

Area of the parallelogram=1/2 | d⃗_⃗1⃗×d⃗_⃗2⃗ |=5 Sq.units ...

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Multiplication with Vectors

Find the area...

Question

Find the area of the parallelogram,whose diagonals are $_{1} = 5^i$ and $_{2} = 2^j$ .

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Solution

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Similar questions

R_{1} = 3^i + 2^j - 7^k

R_{2} = 5^i + 6^j - 3^k

\to a =^i - 2^j + 3^k

\to b = 3^i - 2^j +^k

2^i

2^j

A parallelogram has diagonals expressed as $\to A = 5^i - 4^j + 3^k$ and $\to B = 3^i + 2^j -^k$ . Area of parallelogram is:

^i - 3^j + 2^k, -^i + 2^j

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