Question

Find the area of the parallelogram with adjacent sides formed by $\overrightarrow{P}$ and $\overrightarrow{P}$
where $\overrightarrow{P}=2\hat{i}+3\hat{j}+4\hat{k}$ and $\overrightarrow{Q}=3\hat{i}+2\hat{j}-2\hat{k}$ expressed in meter.

Answer 1

Area of parallelogram is magnitude of cross product of two vectors

so crossprodect is $-14i-18j-5k$

$area=\sqrt{(-14{)}^2+(-18{)}^2+(-5{)}^2}=\sqrt{545}$