Question

Find the area of the pathway of uniform width 1.5 m given that the length of a rectangular field is twice its breadth and the breadth measures 6 m.

• A. $24.75m^2$
• B. $247m^2$
• C. $27m^2$
• D. $270m^2$

Answer 1

The correct option is A

$24.75m^2$

Breadth of the rectangle = EH = FG = 6 m

Length of rectangle = AB = CD = 12 m

Area of the pathway ABCD $=12m\times 1.5m=18m^2$

Area of the pathway EFGH $=6m\times 1.5m=9m^2$ ​

Area (square PQRS) $=1.5m\times 1.5m=2.25m^2$ (note: this area is taken twice)

Total area of pathway = Area (ABCD) + Area (EFGH) - Area (PQRS)

$=(18+9-2.25)m^2=24.75m^2$