Find the area of the pentagon ABCDE, given that EB = 10 cm, DC = 5 cm, AF = 3 cm, and DG = 4 cm.
The area of pentagon ABCDE:
= Area of trapezium BCDE + Area of ∆AEB
=12 × [Sum of parallel sides] × Height + 12 × Base × Height
=12 × (CD + BE)× DG + 12 × BE × AF
=12× (5 + 10) × 4 + 12 × 10 × 3
=15×2+5×3
=30+15
=45 cm2