Question

Question 11

Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm, DN = 3 cm and BM $\perp$ AC, DN $\perp$ AC.

Answer 1

Here, AC = 22 cm, BM = 3 cm, DN = 3 cm
We know that,
Area of a triangle = $\frac{1}{2}\times base\times height$
Now area of quardrilateral ABCDF = Area of $\Delta$ ABC + Area of $\Delta$ ADC
$=\frac{1}{2}\times AC\times BM+\frac{1}{2}\times AC\times DN$
$=\frac{1}{2}\times 22\times 3+\frac{1}{2}\times 22\times 3$
$=3\times 11+3\times 11$
$=33+33$
$=66c{m}^2$
Thus, the area of quadrilateral ABCD is $66c{m}^2$.