Find the area of the quadrilateral ABCD. Here, AC = 22cm.

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Solution

Area of Quadrilateral (ABCD) = Area of Triangle(ΔABC)+Area of Triangle(ΔACD)
$= \frac{1}{2} \times b a s e \times h e i g h t + \frac{1}{2} \times b a s e \times h e i g h t = (\frac{1}{2} \times 22 \times 3) + (\frac{1}{2} \times 22 \times 3) = (11 \times 3) + (11 \times 3) 33 + 33 = 66 c m^{2}$

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Question 11

Find the area of the quadrilateral ABCD.
Here, AC = 22 cm, BM = 3 cm, DN = 3 cm and BM $⊥$ AC, DN $⊥$ AC.

Find the area of the quadrilateral $A B C D$ .

Here, $A C = 22$ cm, $B M = 3$ cm, $D N = 3$ cm, and $B M ⊥ A C, D N ⊥ A C$

In a quadrilateral ABCD AB = 6 cm, BC = 8 cm, CD = 8 cm and AC=10cm.The area of the quadrilateral is 60.67 cm². Find DA.
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