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Question

Find the area of the quadrilateral ABCD, whose vertices are A(1,0),B(5,3),C(2,7) and D(2,4).

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Solution

Area of a quadrilateral=12[(x1y2+x2y3+x3y4+x4y1)(x2y1+x3y2+x4y3+x1y4)]

x1=1,x2=5,x3=2,x4=2,y1=0,y2=3,y3=7 and y4=4

Area of a quadrilateral=12[(1×3+5×7+2×42×0)(5×0+2×32×7+1×4)]

=12[(3+35+80)(0+614+4)]

=12[46+4]=25sq.units

1266145_1366253_ans_495d1eaf88ef4b91962a80a5698f0346.jpg

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Area of a Quadrilateral
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