Find the area of the rectangle whose length and breadth are ( y + 4 ) units and ( y − 3 ) units.

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Solution

Length of rectangle = ( y + 4 ) units

Breadth of rectangle = ( y - 3 ) units

We know that area of rectangle
= length x breadth
= ( y + 4 ) ( y - 3 ) sq.units
= $y^{2}$ + y - 12 sq. units

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Similar questions

The area of a rectangle gets reduced by 9 square units. if its length is reduced by 5 units and breadth is increased by 3 units. However, if the length of this rectangle increases by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.

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According to first condition :
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According to second condition:
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Find the area of the rectangle whose length and breadth are ( y + 4 ) units and ( y − 3 ) units.

Length of rectangle = ( y + 4 ) units Breadth of rectangle = ( y - 3 ) units We know that area of rectangle = length x breadth = ( y + 4 ) ( y - 3 ) sq.units = y2 + y - 12 sq. units

Length of rectangle = ( y + 4 ) units

Breadth of rectangle = ( y - 3 ) units

We know that area of rectangle
= length x breadth
= ( y + 4 ) ( y - 3 ) sq.units
= $y^{2}$ + y - 12 sq. units