Question

Find the area of the region bonded by the parabola $y^2=4ax$ and its latus rectum ?

Answer 1

$\int ydx+\int ydx$ (equal)

$=-{\int }_0^a\sqrt{2axdx}$

$=2\sqrt{2a}x\frac{2}{3}x\frac{3}{2}{\int }_0^a=\frac{4}{3}\sqrt{2}{a}^2$