Find the area of the region bounded by the curve $y^{2} = 4 x$ and the line $x = 3$ .

4 \sqrt{3}

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8 \sqrt{3}

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6

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2 \sqrt{3}

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Solution

The correct option is B $8 \sqrt{3}$
Required area = area of OACO = 2 ( Area of OAB)
$= 2 \int_{0}^{3} 2 \sqrt{x} d x$

$= \frac{8}{3} \times (3)^{3 / 2} = 8 \sqrt{3}$ units.

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Similar questions

Find the area of the region bounded by the curve y² = 4x and the line x = 3

y^{2} = 4 x

x = 3

y^{2} = 4 x, y - a x i s

y = 3

y^{2} = 4 x,

y^{2} = 4 x

x = 3

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