Question

Find the area of the region bounded by the curve $y=4-x^2$, x-axis and the line $x=0$ and $x=2$

• A. $\frac{11}{3}$
• B. $\frac{16}{3}$
• C. $\frac{16}{5}$
• D. $\frac{1}{3}$

Answer 1

The correct option is B $\frac{16}{3}$

$A={\int }_0^{2}4-x^{2}dxA={[4x-\frac{x^3}{3}]}_0^{2}A=[8-\frac{8}{3}]A=\frac{16}{3}$