Find the area of the rhombus having each side equal to 17 cm and one of its diagonals equal to 16 cm.
240 cm2
ABCD is a rhombus in which AB=BC=CD=DA=17 cm
AC=16 cm
Therefore, AO=8cm
In △AOD,
AD2=AO2+OD2
⇒172=82+OD2
⇒289=64+OD2
⇒225=OD2
⇒OD=15
Therefore, BD=2OD
=2×15
=30 cm
Now, area of rhombus
=12×16×30
=240 cm2