Question

Find the area of the right-angled triangle with hypotenuse 40cm and one of the other two sides 24cm

Answer 1

In right angled triangle ABC Hypotenuse $AC=40cm$
One side $AB=24cm$
$BC=\sqrt{A{C}^2-A{B}^2}=\sqrt{{40}^2-{24}^2}=\sqrt{1600-576}=\sqrt{1024}=32cm$
Area
$=\frac{1}{2}AB\times BC=\frac{1}{2}\times 24\times 32c{m}^2=384c{m}^2$