Question

Find the area of the rocket given below.

• A. 40 square units
• B. 41 square units
• C. 42 square units
• D. 43 square units

Answer 1

The correct option is B 41 square units

Area of the rocket = Area of the 3 triangles + Area of the 2 rectangles

Area of Rectangle A
= $\frac{1}{2}$ × Base × Height
= $\frac{1}{2}$ × 6 × 3
= 9 square units

Area of Triangle B = Area of Triangle C
= $\frac{1}{2}$ × 4 × 3
= 6 square units

Length of Rectangle D = Height of Triangle C + 4 units = 8 units

Area of Rectangle D
= Length × Width
= $8\times 2$
= 16 square units

Area of Rectangle E
= $4\times 1$
= 4 square units

Area of the rocket
= 9 + 6 + 6 + 16 + 4
= 41 square units