Question

Find the area of the sector if it subtends ${120}^o$ angle at center of circle whose radius is 21 cm.

• A. 462 $c{m}^2$
• B. 692 $c{m}^2$
• C. 924 $c{m}^2$
• D. 1268 $c{m}^2$

Answer 1

The correct option is A 462 $c{m}^2$

Area of sector = $\frac{Angle}{{360}^o}$$\times$$\pi$$r^2$
= $\frac{{120}^o}{{360}^o}$$\times$$\frac{22}{7}$$\times$${21}^2$
= $\frac{1}{3}$$\times$$\frac{22}{7}$$\times$441
= 462 $c{m}^2$