Question

Find the area of the sector of a circle of radius 14 cm with central angle 45°.

Answer 1

Area of the sector = $\frac{\theta }{360}\times \mathrm{\pi }{r}^2$

$$\begin{gathered} =\frac{45}{360}\times \frac{22}{7}\times 14\times 14 \\ =\frac{1}{8}\times 22\times 2\times 14 \\ =77{\mathrm{cm}}^2 \end{gathered}$$