Question

Find the area of the sector of a circle whose radius is 14 cm and angle of sector is ${45}^o$.

Answer 1

Let O be the centre of the circle with radius 14 cm and OABO be its sector with angle ${45}^o$. Then,

Area of the sector = $\frac{\theta }{360}\times \pi r^2=[\frac{45}{360}\times \frac{22}{7}\times (14{)}^2]=77c{m}^2$