Question

Find the area of the sector whose arc is making an angle of 60∘ at the center of a circle of radius 3.2 cm. What will be the area of the balance sector?

I saw the ans to this ques but did not understand. Can u pls make me understand in a simple way?

Answer 1

Area of sector = ½ r² ∅, where r is the radius and ∅ the angle in radians subtended by the arc at the centre of the circle

=> 1/2 x 3.2 x 3.2 x π/3 60 =π/3 radians
=> 5.35 units

Area of Circle = πr²
= 3.14 x 3.3 x 3.2
=32.15 units

Therefore area of balnce sector = 32.15 - 5.35 = 26.8 units