Find the area of the shaded portion.

256 m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32 m²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
None of the above

Area of shaded region =Area (ABCD)-Area of circular regions

There is one circle and other two semi-circles. Their addition will result in two identical circles.

$∴$ Area of circular region $= 2 \times$ (Area of one circle)

$= 2 \times π r^{2} = 2 \times \frac{22}{7} \times 7 \times 7$

$= 308 c m^{2}$

Area (ABCD)= $A B \times C D = (7 + 14 + 7) c m \times 14 c m$

$= (28 \times 14) c m^{2}$

$= 392 c m^{2}$

$∴$ Area of shaded region $= (392 - 308) c m^{2}$

$= 84 c m^{2}$

Suggest Corrections

Similar questions

Q. Factorise

m^{2} - 256

In the above problem, given that $M_{2} = 2 M_{1} a n d M_{2}$ moves vertically downwards with acceleration a. If the position of the masses are reversed the acceleration of $M_{2}$ down the inclined plane will be

The lateral surface area of a cube is 256 m². The volume of the cube is ______.

m_{2} - m_{1}

the value is

m 1 = \frac{1}{2}

and

m 2 = \frac{3}{2}

Q. Find the area of the shaded portion in the above figure:

Join BYJU'S Learning Program